## How To Find The Area Between Two Polar Curves

How To Find The Area Between Two Polar Curves – Ematics Stack Exchange is a question and answer forum for learners at all levels and experts in related fields. It only takes a minute to register.

Team Stack Overflow is on its way! Once the migration is complete, you will enter your teams at stackoverflowteams.com and will no longer appear on the stackoverflow.com page.

## How To Find The Area Between Two Polar Curves

I know that the graph of \$r = 3 sin theta \$ is different at \$ theta = 0 \$ and at \$ theta = pi \$ why these two limits are not used and why \$ theta \$ only equals \$ pi\$? The graph \$r=3costheta\$ also connects the pole at \$theta=frac, frac\$. Why do they only use \$frac\$?

## Solved] Polar Coordinates Polar Coordinates. 1. List All 4 Identities (…

Note that we are bounded by the area of ​​the red circle \$(\$ lower part \$)\$ with \$theta=0mboxtheta=dfrac\$

Similarly, the purple partial circle \$(\$upper half\$)\$ is bounded by \$theta=dfrac\$ in \$dfrac\$

Note that the error rate is in the first quadrant. This is approximated by \$theta a a left[0, ;frac pi2right]\$.

Let A and B be two points of intersection of the circles, A is (0, 0) and B is (1.5, 1.5). It is easy to see that the arc formed by the center of the circle and A and B has a ratio of \$pi/2\$. Therefore, the area of ​​this segment is \$2.25pi/4\$. The area of ​​the triangle formed by A, B, and the center of the circle is \$2.25 / \$2. Therefore, the area of ​​half of the desired area is \$2.25pi/4 -2.25/2\$ and the desired area is \$5pi/4-2.25 \$